반응공학 2판 솔루션 (the engineering of chemical reactions , schmidt , 2nd edition) 해설집
반응공학 2판 솔루션 (the engineering of chemical reactions , schmidt , 2nd edition) 해설집
반응공학 2판 솔루션 (the engineering of chemical reactions , schmidt , 2nd edition)
반응 공학 2판 솔루션입니다. the engineering of chemical reactions, 2nd edition 저자 schmidt 1장부터 12장 솔루션
반응 공학 2판 솔루션입니다.
the engineering of chemical reactions, 2nd edition
저자 schmidt
1장부터 12장 솔루션Semiconductor Physics and Devices: Basic Principles, 3rd edition Solutions Manual
Chapter 1 Problem Solutions
Chapter 1
Problem Solutions
1.1 (a) fcc: 8 corner atoms × 1/8 = 1 atom 6 face atoms × ½ = 3 atoms Total of 4 atoms per unit cell (b) bcc: 8 corner atoms × 1/8 = 1 atom 1 enclosed atom = 1 atom Total of 2 atoms per unit cell (c) Diamond: 8 corner atoms × 1/8 = 1 atom 6 face atoms × ½ = 3 atoms 4 enclosed atoms = 4 atoms Total of 8 atoms per unit cell 1.2 (a) 4 Ga atoms per unit cell Density = 4 atoms per cell, so atom vol. = 4 Then 4 Ratio =
FG 4πr IJ H3K
3
16 2 r (c) Body-centered cubic lattice 4 d = 4r = a 3 ⇒ a = r 3 Unit cell vol. = a =
3
FG 4πr IJ H 3 K × 100% ⇒
3 3
Ratio = 74%
F 4 rI H 3K
3
2 atoms per cell, so atom vol. = 2 Then
FG 4πr IJ H3K
3
b
4
?8
5.65 x10
g
3
⇒
22 ?3
Density of Ga = 2.22 x10 cm
22
4 As atoms per unit cell, so that Density of As = 2.22 x10 cm (b) 8 Ge atoms per unit cell 8 ⇒
자료출처 : http://www.ALLReport.co.kr/search/Detail.asp?pk=11041792&sid=sanghyun7776&key=
[문서정보]
문서분량 : 216 Page
파일종류 : PDF 파일
자료제목 : 반응공학 2판 솔루션 (the engineering of chemical reactions , schmidt , 2nd edition)
파일이름 : 반응공학 solution[2].pdf
키워드 : 솔루션,반응공학,2판,the,engineering,of,chemical,reactions,schmidt,2nd
자료No(pk) : 11041792
반응공학 2판 솔루션 (the engineering of chemical reactions , schmidt , 2nd edition)
반응 공학 2판 솔루션입니다. the engineering of chemical reactions, 2nd edition 저자 schmidt 1장부터 12장 솔루션
반응 공학 2판 솔루션입니다.
the engineering of chemical reactions, 2nd edition
저자 schmidt
1장부터 12장 솔루션Semiconductor Physics and Devices: Basic Principles, 3rd edition Solutions Manual
Chapter 1 Problem Solutions
Chapter 1
Problem Solutions
1.1 (a) fcc: 8 corner atoms × 1/8 = 1 atom 6 face atoms × ½ = 3 atoms Total of 4 atoms per unit cell (b) bcc: 8 corner atoms × 1/8 = 1 atom 1 enclosed atom = 1 atom Total of 2 atoms per unit cell (c) Diamond: 8 corner atoms × 1/8 = 1 atom 6 face atoms × ½ = 3 atoms 4 enclosed atoms = 4 atoms Total of 8 atoms per unit cell 1.2 (a) 4 Ga atoms per unit cell Density = 4 atoms per cell, so atom vol. = 4 Then 4 Ratio =
FG 4πr IJ H3K
3
16 2 r (c) Body-centered cubic lattice 4 d = 4r = a 3 ⇒ a = r 3 Unit cell vol. = a =
3
FG 4πr IJ H 3 K × 100% ⇒
3 3
Ratio = 74%
F 4 rI H 3K
3
2 atoms per cell, so atom vol. = 2 Then
FG 4πr IJ H3K
3
b
4
?8
5.65 x10
g
3
⇒
22 ?3
Density of Ga = 2.22 x10 cm
22
4 As atoms per unit cell, so that Density of As = 2.22 x10 cm (b) 8 Ge atoms per unit cell 8 ⇒
자료출처 : http://www.ALLReport.co.kr/search/Detail.asp?pk=11041792&sid=sanghyun7776&key=
[문서정보]
문서분량 : 216 Page
파일종류 : PDF 파일
자료제목 : 반응공학 2판 솔루션 (the engineering of chemical reactions , schmidt , 2nd edition)
파일이름 : 반응공학 solution[2].pdf
키워드 : 솔루션,반응공학,2판,the,engineering,of,chemical,reactions,schmidt,2nd
자료No(pk) : 11041792
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